JavaScript Password Validator
Write a program to validate password using regex expression
Youtube Video: https://youtu.be/piJsqtEQ8_Q
Problem Statement:
Write a program that takes in a string as input and evaluates it as a valid password. The password is valid if it has at a minimum 2 numbers, 2 of the following special characters ('!', '@', '#', '$', '%', '&', '*'), and a length of at least 7 characters.
If the password passes the check, output 'Strong', else output 'Weak'.
Input Format:
A string representing the password to evaluate.
Output Format:
A string that says 'Strong' if the input meets the requirements, or 'Weak', if not.
Sample Input:
Hello@$World19
Sample Output:
Strong
passwordValidator.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Password Validator</title>
<script src="passwordValidator.js"></script>
</head>
<body>
<input id="password" />
<button onclick="validate()">Validate</button>
</body>
</html>
passwordValidator.js
function validate() {
// This problem can be solved using regex
// First get the value entered by the user in the input box
const inputValue = document.getElementById('password').value;
if (inputValue) {
// Let us define the regex which will validate the input
const regex = /(?=.*[0-9]{2,})(?=.*[!@#$%&*]{2,})[a-zA-Z0-9!@#$%&*]{7,}/;
// Here, (?=.*[0-9]{2,}) will check if the string entered has atleast 2 numbers
// (?=.*[!@#$%&*]{2,}) will check if the string entered has atleast 2 of the symbols defined in []
// and the last part will check all the entered characters are at least 7 length
// This type of regex is called lookahead assertions
if (regex.test(inputValue)) {
alert('Strong')
} else {
alert('Weak');
}
}
}
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